It's coming out twice because your looping is wrong, as explained (indirectly) at http://www.parashift.com/c++-faq-lite/input-output.html#faq-15.5 (while (iss)
is not dissimilar from while (iss.eof())
in this scenario).
Specifically, on the third loop iteration, iss >> n
succeeds and gets your 3
, and leaves the stream in a good state. The loop then runs a fourth time due to this good state, and it's not until the next (fourth) iss >> n
subsequently fails that the loop condition is broken. But before that fourth iteration ends, you still output n
... a fourth time.
Try:
#include <string>
#include <iostream>
#include <sstream>
#include <vector>
using namespace std;
int main()
{
string s = "1 2 3";
istringstream iss(s);
int n;
while (iss >> n) {
cout << "* " << n << endl;
}
}
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