OGeek|极客世界-中国程序员成长平台 › 门户 ›编程› AJAX› AJAX编程经验 › 查看内容

AJAX 二级级联菜单实现代码

2022-2-5 17:00| 发布者: 菜鸟教程小白| 查看: 244| 评论: 0|原作者: [db:作者]|来自: [db:来源]

摘要: AJAX实现二级级联菜单，用PHP完成

客户端代码：

 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" /> 
<title>无标题文档</title> 
</head> 
<script type="text/javascript"> 
var xmlHttp; 
var a =new Array(); 
function createXMLHttpRequest(){ 
if(window.ActiveXObject){ 
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); 
} 
else if(window.XMLHttpRequest){ 
xmlHttp=new XMLHttpRequest(); 
} 
} 
function send_request(){ 
createXMLHttpRequest(); 
var year = document.getElementById("year"); 
var url = "check_2.php?page="+escape(year.value); 
xmlHttp.open("GET",url,true); 
xmlHttp.onreadystatechange = checkit; 
xmlHttp.send(null); 
} 
function checkit(){ 
if(xmlHttp.readystate == 4){ 
if(xmlHttp.status == 200){ 
showChild(); 
} 
} 
} 
function showChild(){ 
var xmlDoc=xmlHttp.responseXML; 
var content=xmlDoc.getElementsByTagName("city"); 
for(var i=0;i<content.length;i++){ 
var y=content[i]; 
a[i]=y.childNodes[0].data; 
} 
show1(); 
} 
function show1(){ 
var obj=document.getElementById("name"); 
var number=obj.length; 
for(var j=obj.length-1;j>=0;j--){ 
obj.removeChild(obj.childNodes.item(j)); 
} 
for(var i=0;i<a.length;i++){ 
var opt=document.createElement("OPTION"); 
opt.text=a[i]; 
obj.add(opt); 
} 
} 
</script> 
<body> 
年份：<select id="year" onchange="send_request()"> 
<option value="0">请选择</option> 
<option value="1">1996-2006</option> 
<option value="2">1986-1995</option> 
<option value="3">1971-1985</option> 
<option value="4">1970以前</option> 
</select> 
子目录:<select id="name"> 
<option value="0">请选择</option> 
</select> 
</body> 
</html> 

服务器端代码：

复制代码代码如下:

 
<?php 
header('Content-type: text/xml'); 
$xml="<?xml version='1.0' encoding='GB2312'?>"; 
$year = $_GET["page"]; 
$content = $xml."<contents>"; 
if($year == "1"){ 
$content = $content."<city>1</city><city>11</city></contents>"; 
} 
else if($year == '2'){ 
$content = $content."<city>2</city><city>12</city></contents>"; 
} 
else if($year == '3'){ 
$content = $content."<city>3</city><city>13</city></contents>"; 
} 
else if($year == '4'){ 
$content = $content."<city>4</city><city>14</city></contents>"; 
} 
echo $content; 
?> 