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Python rules.Pattern类代码示例

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

本文整理汇总了Python中mathics.core.rules.Pattern的典型用法代码示例。如果您正苦于以下问题:Python Pattern类的具体用法?Python Pattern怎么用?Python Pattern使用的例子?那么恭喜您, 这里精选的类代码示例或许可以为您提供帮助。



在下文中一共展示了Pattern类的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。

示例1: init

 def init(self, expr):
     super(PatternObject, self).init(expr)
     if self.arg_counts is not None:
         if len(expr.leaves) not in self.arg_counts:
             self.error_args(len(expr.leaves), *self.arg_counts)
     self.expr = expr
     self.head = Pattern.create(expr.head)
     self.leaves = [Pattern.create(leaf) for leaf in expr.leaves]
开发者ID:fleeaway,项目名称:Mathics,代码行数:8,代码来源:base.py


示例2: apply

    def apply(self, f, x, evaluation):
        'D[f_, x_?NotListQ]'

        if f == x:
            return Integer(1)
        elif not f.is_atom() and len(f.leaves) == 1 and f.leaves[0] == x:
            return Expression(
                Expression(Expression('Derivative', Integer(1)), f.head), x)
        elif not f.is_atom() and len(f.leaves) == 1:
            g = f.leaves[0]
            return Expression(
                'Times', Expression('D', Expression(f.head, g), g),
                Expression('D', g, x))
        elif not f.is_atom() and len(f.leaves) > 1:
            def summand(leaf, index):
                if leaf.same(x):
                    result = Expression(Expression(
                        Expression(
                            'Derivative',
                            *([Integer(0)] * (index) + [Integer(1)] +
                              [Integer(0)] * (len(f.leaves) - index - 1))),
                        f.head), *f.leaves)
                else:
                    result = Expression('D', f, leaf)
                return Expression('Times', result, Expression('D', leaf, x))
            x_pattern = Pattern.create(x)
            result = Expression(
                'Plus', *[
                    summand(leaf, index) for index, leaf in enumerate(f.leaves)
                    if not leaf.is_free(x_pattern, evaluation)])
            if len(result.leaves) == 1:
                return result.leaves[0]
            else:
                return result
开发者ID:ashtonbaker,项目名称:Mathics,代码行数:34,代码来源:calculus.py


示例3: apply

 def apply(self, expr, patterns, f, evaluation):
     'Reap[expr_, {patterns___}, f_]'
     
     patterns = patterns.get_sequence()
     sown = [(Pattern.create(pattern), []) for pattern in patterns]
     
     def listener(e, tag):
         result = False
         for pattern, items in sown:
             if pattern.does_match(tag, evaluation):
                 for item in items:
                     if item[0].same(tag):
                         item[1].append(e)
                         break
                 else:
                     items.append((tag, [e]))
                 result = True
         return result
     
     evaluation.add_listener('sow', listener)
     try:
         result = expr.evaluate(evaluation)
         items = []
         for pattern, tags in sown:
             list = Expression('List')
             for tag, elements in tags:
                 list.leaves.append(Expression(f, tag, Expression('List', *elements)))
             items.append(list)
         return Expression('List', result, Expression('List', *items))
     finally:
         evaluation.remove_listener('sow', listener)
开发者ID:bwright,项目名称:Mathics,代码行数:31,代码来源:lists.py


示例4: apply

    def apply(self, expr, pattern, test, evaluation):
        'ArrayQ[expr_, pattern_, test_]'

        pattern = Pattern.create(pattern)

        dims = [len(expr.get_leaves())]  # to ensure an atom is not an array

        def check(level, expr):
            if not expr.has_form('List', None):
                test_expr = Expression(test, expr)
                if test_expr.evaluate(evaluation) != Symbol('True'):
                    return False
                level_dim = None
            else:
                level_dim = len(expr.leaves)

            if len(dims) > level:
                if dims[level] != level_dim:
                    return False
            else:
                dims.append(level_dim)
            if level_dim is not None:
                for leaf in expr.leaves:
                    if not check(level + 1, leaf):
                        return False
            return True

        if not check(0, expr):
            return Symbol('False')

        depth = len(dims) - 1  # None doesn't count
        if not pattern.does_match(Integer(depth), evaluation):
            return Symbol('False')
        return Symbol('True')
开发者ID:KarlHeitmann,项目名称:Mathics,代码行数:34,代码来源:tensors.py


示例5: apply

    def apply(self, expr, form, evaluation):
        'FreeQ[expr_, form_]'

        form = Pattern.create(form)
        if expr.is_free(form, evaluation):
            return Symbol('True')
        else:
            return Symbol('False')
开发者ID:Darkoe,项目名称:Mathics,代码行数:8,代码来源:structure.py


示例6: apply

 def apply(self, expr, form, evaluation):
     'FreeQ[expr_, form_]'
     
     """def is_free(sub):
         for vars, rest in form.match(sub, {}, evaluation, fully=False):
             return False
         if sub.is_atom():
             return True
         else:
             return is_free(sub.head) and all(is_free(leaf) for leaf in sub.leaves)"""
         
     form = Pattern.create(form)
     if expr.is_free(form, evaluation):
         return Symbol('True')
     else:
         return Symbol('False')
开发者ID:TheJokerX47,项目名称:Mathics,代码行数:16,代码来源:structure.py


示例7: apply

 def apply(self, eqs, vars, evaluation):
     'Solve[eqs_, vars_]'
     
     vars_original = vars
     head_name = vars.get_head_name()
     if head_name == 'List':
         vars = vars.leaves
     else:
         vars = [vars]
     for var in vars:
         if (var.is_atom() and not var.is_symbol()) or head_name in ('Plus', 'Times', 'Power'):
             evaluation.message('Solve', 'ivar', vars_original)
             return
     eqs_original = eqs
     if eqs.get_head_name() in ('List', 'And'):
         eqs = eqs.leaves
     else:
         eqs = [eqs]
     sympy_eqs = []
     sympy_denoms = []
     for eq in eqs:
         symbol_name = eq.get_name()
         if symbol_name == 'True':
             #return Expression('List', Expression('List'))
             pass
         elif symbol_name == 'False':
             return Expression('List')
         elif not eq.has_form('Equal', 2):
             return evaluation.message('Solve', 'eqf', eqs_original)
         else:
             left, right = eq.leaves
             left = left.to_sympy()
             right = right.to_sympy()
             #vars_sympy = [var.to_sympy() for var in vars]
             eq = left - right
             eq = sympy.together(eq)
             eq = sympy.cancel(eq)                
             sympy_eqs.append(eq)
             numer, denom = eq.as_numer_denom()
             sympy_denoms.append(denom)
     #eqs = actual_eqs
     
     #left, right = eq.leaves
     
     vars_sympy = [var.to_sympy() for var in vars]
     
     # delete unused variables to avoid SymPy's
     # PolynomialError: Not a zero-dimensional system
     # in e.g. Solve[x^2==1&&z^2==-1,{x,y,z}]
     all_vars = vars[:]
     all_vars_sympy = vars_sympy[:]
     #for index, var in enumerate(all_vars):
     #    if eqs_original.is_free(var, evaluation):
     vars = []
     vars_sympy = []   
     for var, var_sympy in zip(all_vars, all_vars_sympy):
         pattern = Pattern.create(var)
         if not eqs_original.is_free(pattern, evaluation):
             vars.append(var)
             vars_sympy.append(var_sympy)
     
     def transform_dict(sols):
         #print "Transform %s" % sols
         if not sols:
             yield sols
         for var, sol in sols.iteritems():
             rest = sols.copy()
             del rest[var]
             rest = transform_dict(rest)
             if not isinstance(sol, (tuple, list)):
                 #print "Convert %s (type %s)" % (sol, type(sol))
                 sol = [sol]
             if not sol:
                 for r in rest:
                     #print "Yield %s" % r
                     yield r
             else:
                 for r in rest:
                     for item in sol:
                         #print "Yield %s with new %s" % (r, item)
                         new_sols = r.copy()
                         new_sols[var] = item
                         yield new_sols
             break
     
     def transform_solution(sol):
         #if isinstance(sol, (list, tuple)):
         if not isinstance(sol, dict):
             if not isinstance(sol, (list, tuple)):
                 sol = [sol]
             sol = dict(zip(vars_sympy, sol))
         #return sol
         return transform_dict(sol)
     
     if not sympy_eqs:
         sympy_eqs = True
     elif len(sympy_eqs) == 1:
         sympy_eqs = sympy_eqs[0]
         
     #eq = left - right
#.........这里部分代码省略.........
开发者ID:cjiang,项目名称:Mathics,代码行数:101,代码来源:calculus.py



注:本文中的mathics.core.rules.Pattern类示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。


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Python pattern.Pattern类代码示例发布时间:2022-05-27
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