http://stackoverflow.com/questions/5703705/print-current-directory-using-perl?rq=1

1）

The following get the script's directory, which is not the same as the current directory. It's not clear which one you want.

use Cwd qw( abs_path );

useFile::Basename qw( dirname );

say dirname(abs_path($0));

or

usePath::Class qw( file );

say file($0)->absolute->dir;

or

useCwd qw( abs_path );

use Path::Class qw( file );

say file(abs_path($0))->dir;

The middle one handles symlinks different than the other two, I believe.

2）

To get the current working directory (pwd on many systems), you could use cwd() instead of abs_path:

useCwd qw();

my $path =Cwd::cwd();

print "$path\n";

Or abs_path without an argument:

useCwd qw();

my $path =Cwd::abs_path();

print "$path\n";

See the Cwd docs for details.

To get the directory your perl file is in from outside of the directory:

useFile::Basename qw();

my($name, $path, $suffix)=File::Basename::fileparse($0);

print "$path\n";

See the File::Basename docs for more details.

3）

You could use FindBin:

use FindBin '$RealBin';

print "$RealBin\n";

FindBin is a standard module that is installed when you install Perl. To get a list of the standard pragmatics and modules, see perldoc perlmodlib.

完！