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标题: android - super 强大的 Android 同时播放和录制 [打印本页]

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作者: 菜鸟教程小白    时间: 2022-12-9 06:48
标题: android - super 强大的 Android 同时播放和录制

我正在使用 Superpowered Android C++ 库开发混音器，我在录制时遇到播放器问题，播放器没有播放，只有录音机在录制。下面是代码，谁能指导我哪里放错地方了

bool processRecording(short int *input, unsigned int numberOfSamples) {
pthread_mutex_lock(&mutex);
if (askRecording) {
    unsigned int data = 0;

       SuperpoweredShortIntToFloat(input, stereoBufferRecording, numberOfSamples);
       data = recorder->process(stereoBufferRecording, NULL, numberOfSamples);

       playerA->process( musicBuffer, false, numberOfSamples, 0.5f );
       SuperpoweredShortIntToFloat(input, stereoBufferRecording, numberOfSamples);

       SuperpoweredFloatToShortInt(musicBuffer, input, numberOfSamples);

       pthread_mutex_unlock(&mutex);
       return true;
       }
pthread_mutex_unlock(&mutex);
return false;
}

有人知道把它放在正确的地方吗？

@Gabor 建议的更改之后是代码 fragment

bool processRecording(short int *input, unsigned int numberOfSamples) {

pthread_mutex_lock(&mutex);
if (askRecording) {
    unsigned int data = 0;
    SuperpoweredShortIntToFloat(input, stereoBufferRecording, numberOfSamples);

    playerA->process( musicBuffer, false, numberOfSamples, 1.0f );

//=====================================================================================
 // ================== Mixing Two Buffer ==================

    mixerInputs[0] = musicBuffer;
    mixerInputs[1] = stereoBufferRecording;
    mixerInputs[2] = NULL;
    mixerInputs[3] = NULL;

    mixerOutputs[0] = outputBuffer;
    mixerOutputs[1] = NULL;

    float inputLevels[] = { 0.5f, 0.5f, 1.0f, 1.0f, 1.0f, 1.0f, 1.0f, 1.0f };
    float outputLevels[] = { 1.0f, 1.0f };
    __android_log_print(ANDROID_LOG_INFO, "NativeSuperpoweredRecorder  ", " processRecording 2>>");
    mixerBackend->process(mixerInputs, mixerOutputs, inputLevels, outputLevels, NULL, NULL, numberOfSamples);

//=====================================================================================

    data = recorder->process(mixerOutputs[0], NULL, numberOfSamples);
    SuperpoweredFloatToShortInt(musicBuffer, input, numberOfSamples);
    pthread_mutex_unlock(&mutex);
    return true;
}
pthread_mutex_unlock(&mutex);

return false; }

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Best Answer-推荐答案

这是您在代码中所做的:

输入->stereoBufferRecording->录音机

输入->stereoBufferRecording->?

播放器->musicBuffer->输入

当 askRecording 为 false 时，播放器根本不玩。

我猜“输入”与“输出”的缓冲区相同？

关于android - super 强大的 Android 同时播放和录制，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/45764824/

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