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in Technique[技术] by (71.8m points)

关于js类型转换的问题

[] == {}  // false

这是为什么呢?
另外

{} == [] // error

直接报错


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by (71.8m points)

js中块结构和对象的写法都是{},默认的语法前面的{}会被当作块结构,就像你下面的写法,所以这里会因为语法问题抛出错误,一般的需要用括号包起来:({}) == []

再回到类型转换,两个引用类型的值进行比较,无论是相等还是全等,都是进行值比较,而不会发生类型转换。


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